matrix.shape

matrix.shape

Tuple of array dimensions.

Notes

May be used to ?reshape? the array, as long as this would not require a change in the total number of elements

Examples

>>> x = np.array([1, 2, 3, 4])
>>> x.shape
(4,)
>>> y = np.zeros((2, 3, 4))
>>> y.shape
(2, 3, 4)
>>> y.shape = (3, 8)
>>> y
array([[ 0.,  0.,  0.,  0.,  0.,  0.,  0.,  0.],
       [ 0.,  0.,  0.,  0.,  0.,  0.,  0.,  0.],
       [ 0.,  0.,  0.,  0.,  0.,  0.,  0.,  0.]])
>>> y.shape = (3, 6)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: total size of new array must be unchanged

Links:

https://docs.scipy.org/doc/numpy-1.11.0/reference/generated/numpy.matrix.shape.html

doc_NumPy

2025-01-10 15:47:30

Comments

Popular Articles

Matrix#Matrix new Matrix(a, b, c, d, tx, ty) The Matrix is a 3x3 matrix mostly used for display transforms within the renderer. It is represented like so: | a |

matrix.getI() matrix.getI() [source] Returns the (multiplicative) inverse of invertible self. Parameters: None Returns: ret : matrix object If self is non-

matrix.argpartition() matrix.argpartition(kth, axis=-1, kind='introselect', order=None) Returns the indices that would partition this array. Refer to numpy.argpartitio

matrix.prod() matrix.prod(axis=None, dtype=None, out=None) [source] Return the product of the array elements over the given axis. Refer to prod for full docume

matrix.choose() matrix.choose(choices, out=None, mode='raise') Use an index array to construct a new array from a set of choices. Refer to numpy.choose for full