(PHP 4, PHP 5, PHP 7)
Create a new image from file or URL
resource imagecreatefromjpeg ( string $filename )
imagecreatefromjpeg() returns an image identifier representing the image obtained from the given filename.
Tip
A URL can be used as a filename with this function if the fopen wrappers have been enabled. See fopen() for more details on how to specify the filename. See the Supported Protocols and Wrappers for links to information about what abilities the various wrappers have, notes on their usage, and information on any predefined variables they may provide.
Parameters:
filename
Path to the JPEG image.
Returns:
Returns an image resource identifier on success, FALSE on errors.
Notes:
JPEG support is only available if PHP was compiled against GD-1.8 or later.
Examples:
Example to handle an error during loading of a JPEG
<?php
function LoadJpeg($imgname)
{
/* Attempt to open */
$im = @imagecreatefromjpeg($imgname);
/* See if it failed */
if(!$im)
{
/* Create a black image */
$im = imagecreatetruecolor(150, 30);
$bgc = imagecolorallocate($im, 255, 255, 255);
$tc = imagecolorallocate($im, 0, 0, 0);
imagefilledrectangle($im, 0, 0, 150, 30, $bgc);
/* Output an error message */
imagestring($im, 1, 5, 5, 'Error loading ' . $imgname, $tc);
}
return $im;
}
header('Content-Type: image/jpeg');
$img = LoadJpeg('bogus.image');
imagejpeg($img);
imagedestroy($img);
?>
The above example will output something similar to:
Please login to continue.