jQuery.isFunction()

Determine if the argument passed is a JavaScript function object.

Note: As of jQuery 1.3, functions provided by the browser like alert() and DOM element methods like getAttribute() are not guaranteed to be detected as functions in browsers such as Internet Explorer.

jQuery.isFunction( obj )

version added: 1.2

obj

PlainObject

Object to test whether or not it is a function.

Examples:

Test a few parameter examples.

<!doctype html>
<html lang="en">
<head>
  <meta charset="utf-8">
  <title>jQuery.isFunction demo</title>
  <style>
  div {
    color: blue;
    margin: 2px;
    font-size: 14px;
  }
  span {
    color: red;
  }
  </style>
  <script src="https://code.jquery.com/jquery-1.10.2.js"></script>
</head>
<body>
 
<div>jQuery.isFunction( objs[ 0 ] ) = <span></span></div>
<div>jQuery.isFunction( objs[ 1 ] ) = <span></span></div>
<div>jQuery.isFunction( objs[ 2 ] ) = <span></span></div>
<div>jQuery.isFunction( objs[ 3 ] ) = <span></span></div>
<div>jQuery.isFunction( objs[ 4 ] ) = <span></span></div>
 
<script>
function stub() {}
var objs = [
  function() {},
  { x:15, y:20 },
  null,
  stub,
  "function"
];
 
jQuery.each( objs, function( i ) {
  var isFunc = jQuery.isFunction( objs[ i ]);
  $( "span" ).eq( i ).text( isFunc );
});
</script>
 
</body>
</html>

Finds out if the parameter is a function.

$.isFunction(function() {});

Links:

http://api.jquery.com/jquery.isfunction

doc_jQuery

2016-03-27 13:48:35

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