Login Register

audioop.findfactor()

audioop.findfactor(fragment, reference)

Return a factor F such that rms(add(fragment, mul(reference, -F))) is minimal, i.e., return the factor with which you should multiply reference to make it match as well as possible to fragment. The fragments should both contain 2-byte samples.

The time taken by this routine is proportional to len(fragment).

Links:

https://docs.python.org/3.5/library/audioop.html#audioop.findfactor

doc_python

2016-10-07 17:27:14

Comments

Leave a Comment

Please login to continue.

Popular Articles

audioop.max() audioop.max(fragment, width) Return the maximum of the absolute value of all samples in a fragment.

audioop.adpcm2lin() audioop.adpcm2lin(adpcmfragment, width, state) Decode an Intel/DVI ADPCM coded fragment to a linear fragment. See the description of lin2adpcm() f

audioop.ulaw2lin() audioop.ulaw2lin(fragment, width) Convert sound fragments in u-LAW encoding to linearly encoded sound fragments. u-LAW encoding always uses 8 bits

audioop.minmax() audioop.minmax(fragment, width) Return a tuple consisting of the minimum and maximum values of all samples in the sound fragment.

audioop.alaw2lin() audioop.alaw2lin(fragment, width) Convert sound fragments in a-LAW encoding to linearly encoded sound fragments. a-LAW encoding always uses 8 bits