match.groups(default=None)
Return a tuple containing all the subgroups of the match, from 1 up to however many groups are in the pattern. The default argument is used for groups that did not participate in the match; it defaults to None.
For example:
1 2 3 | >>> m = re.match(r"(\d+)\.(\d+)", "24.1632")>>> m.groups()('24', '1632') |
If we make the decimal place and everything after it optional, not all groups might participate in the match. These groups will default to None unless the default argument is given:
1 2 3 4 5 | >>> m = re.match(r"(\d+)\.?(\d+)?", "24")>>> m.groups() # Second group defaults to None.('24', None)>>> m.groups('0') # Now, the second group defaults to '0'.('24', '0') |
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