Login Register

re.regex.sub()

regex.sub(repl, string, count=0)

Identical to the sub() function, using the compiled pattern.

Links:

https://docs.python.org/3.5/library/re.html#re.regex.sub

doc_python

2016-10-07 17:41:19

Comments

Leave a Comment

Please login to continue.

Popular Articles

re.regex.match() regex.match(string[, pos[, endpos]]) If zero or more characters at the beginning of string match this regular expression, return a corresponding m

re.regex.findall() regex.findall(string[, pos[, endpos]]) Similar to the findall() function, using the compiled pattern, but also accepts optional pos and endpos par

re.regex.finditer() regex.finditer(string[, pos[, endpos]]) Similar to the finditer() function, using the compiled pattern, but also accepts optional pos and endpos p

re.regex.groupindex regex.groupindex A dictionary mapping any symbolic group names defined by (?P<id>) to group numbers. The dictionary is empty if no symbolic

re.regex.subn() regex.subn(repl, string, count=0) Identical to the subn() function, using the compiled pattern.