Login Register

zipfile.ZipFile.infolist()

ZipFile.infolist()

Return a list containing a ZipInfo object for each member of the archive. The objects are in the same order as their entries in the actual ZIP file on disk if an existing archive was opened.

Links:

https://docs.python.org/3.5/library/zipfile.html#zipfile.ZipFile.infolist

doc_python

2016-10-07 17:48:41

Comments

Leave a Comment

Please login to continue.

Popular Articles

zipfile.ZipFile class zipfile.ZipFile(file, mode='r', compression=ZIP_STORED, allowZip64=True) Open a ZIP file, where file can be either a path to a file (a strin

zipfile.ZipFile.namelist() ZipFile.namelist() Return a list of archive members by name.

zipfile.ZipFile.testzip() ZipFile.testzip() Read all the files in the archive and check their CRC’s and file headers. Return the name of the first bad file, or else return

zipfile.ZipFile.extract() ZipFile.extract(member, path=None, pwd=None) Extract a member from the archive to the current working directory; member must be its full name or a

zipfile.ZipFile.getinfo() ZipFile.getinfo(name) Return a ZipInfo object with information about the archive member name. Calling getinfo() for a name not currently contained