strncpy

Defined in header `<string.h>`
	(1)
char strncpy( char dest, const char *src, size_t count );		(until C99)
char strncpy( char restrict dest, const char *restrict src, size_t count );		(since C99)
errno_t strncpy_s(char restrict dest, rsize_t destsz, const char restrict src, rsize_t count);		(2)	(since C11)

1) Copies at most count characters of the character array pointed to by src (including the terminating null character, but not any of the characters that follow the null character) to character array pointed to by dest.

If count is reached before the entire array src was copied, the resulting character array is not null-terminated.

If, after copying the terminating null character from src, count is not reached, additional null characters are written to dest until the total of count characters have been written.

The behavior is undefined if the dest array is not large enough. The behavior is undefined if the character arrays overlap. The behavior is undefined if either dest or src is not a pointer to a character array.

2) Same as (1), except that the function does not continue writing zeroes into the destination array to pad up to count, it stops after writing the terminating null character (if there was no null in the source, it writes one at dest[count] and then stops). Also, the following errors are detected at runtime and call the currently installed constraint handler function:

src or dest is a null pointer
destsz or count is zero or greater than RSIZE_MAX
count is greater or equal destsz, but destsz is less or equal strnlen_s(src, count), in other words, truncation would occur
overlap would occur between the source and the destination strings

The behavior is undefined if the size of the character array pointed to by dest < strnlen_s(src, destsz) <= destsz; in other words, an erroneous value of destsz does not expose the impending buffer overflow. The behavior is undefined if the size of the character array pointed to by src < strnlen_s(src, count) < destsz; in other words, an erroneous value of count does not expose the impending buffer overflow.

As all bounds-checked functions, strncpy_s is only guaranteed to be available if __STDC_LIB_EXT1__ is defined by the implementation and if the user defines __STDC_WANT_LIB_EXT1__ to the integer constant 1 before including string.h.

Parameters

dest	-	pointer to the character array to copy to
src	-	pointer to the character array to copy from
count	-	maximum number of characters to copy
destsz	-	the size of the destination buffer

Return value

1) returns a copy of dest

2) returns zero on success, returns non-zero on error. Also, on error, writes zero to dest[0] (unless dest is a null pointer or destsz is zero or greater than RSIZE_MAX) and may clobber the rest of the destination array with unspecified values.

Notes

As corrected by the post-C11 DR 468, strncpy_s, unlike strcpy_s, is only allowed to clobber the remainder of the destination array if an error occurs.

Unlike strncpy, strncpy_s does not pad the destination array with zeroes, This is a common source of errors when converting existing code to the bounds-checked version.

Although truncation to fit the destination buffer is a security risk and therefore a runtime constraints violation for strncpy_s, it is possible to get the truncating behavior by specifying count equal to the size of the destination array minus one: it will copy the first count bytes and append the null terminator as always: strncpy_s(dst, sizeof dst, src, (sizeof dst)-1);

Example

#define __STDC_WANT_LIB_EXT1__ 1
#include <string.h>
#include <stdio.h>
#include <stdlib.h>
 
int main(void)
{
    char src[] = "hi";
    char dest[6] = "abcdef"; // no null terminator
    strncpy(dest, src, 5); // writes five characters 'h', 'i', '\0', '\0', '\0' to dest
    printf("strncpy(dest, src, 5) to a 6-byte dest gives : ");
    for(size_t n = 0; n < sizeof dest; ++n) {
        char c = dest[n];
        c ? printf("'%c' ", c) : printf("'\\0' ");
    }
 
    printf("\nstrncpy(dest2, src, 2) to a 2-byte dst gives : ");
    char dest2[2];
    strncpy(dest2, src, 2); // truncation: writes two characters 'h', 'i', to dest2
    for(size_t n = 0; n < sizeof dest2; ++n) {
        char c = dest2[n];
        c ? printf("'%c' ", c) : printf("'\\0' ");
    }
    printf("\n");
 
#ifdef __STDC_LIB_EXT1__
    set_constraint_handler_s(ignore_handler_s);
    char dst1[6], src1[100] = "hello";
    int r1 = strncpy_s(dst1, 6, src1, 100);      // writes 0 to r1, 6 characters to dst1
    printf("dst1 = \"%s\", r1 = %d\n", dst1,r1); // 'h','e','l','l','o','\0' to dst1
 
    char dst2[5], src2[7] = {'g','o','o','d','b','y','e'};
    int r2 = strncpy_s(dst2, 5, src2, 7);        // copy overflows the destination array
    printf("dst2 = \"%s\", r2 = %d\n", dst2,r2); // writes nonzero to r2,'\0' to dst2[0]
 
    char dst3[5];
    int r3 = strncpy_s(dst3, 5, src2, 4);        // writes 0 to r3, 5 characters to dst3
    printf("dst3 = \"%s\", r3 = %d\n", dst3,r3); // 'g', 'o', 'o', 'd', '\0' to dst3 
#endif
}

Possible output:

strncpy(dest, src, 5) to a 6-byte dst gives : 'h' 'i' '\0' '\0' '\0' 'f'
strncpy(dest2, src, 2) to a 2-byte dst gives : 'h' 'i'
dst1 = "hello", r1 = 0
dst2 = "", r2 = 22
dst3 = "good", r3 = 0

References

C11 standard (ISO/IEC 9899:2011):
- 7.24.2.4 The strncpy function (p: 363-364)
- K.3.7.1.4 The strncpy_s function (p: 616-617)
C99 standard (ISO/IEC 9899:1999):
- 7.21.2.4 The strncpy function (p: 326-327)
C89/C90 standard (ISO/IEC 9899:1990):
- 4.11.2.4 The strncpy function

strcpystrcpy_s (C11)	copies one string to another (function)
memcpymemcpy_s (C11)	copies one buffer to another (function)
C++ documentation for `strncpy`