Queries the alignment requirement of its operand type.
Syntax
_Alignof( type-name ) | (since C11) |
This operator is typically used through the convenience macro alignof
, which is provided in the header stdalign.h
.
Explanation
Returns the alignment requirement of the type named by type-name. If type-name is an array type, the result is the alignment requirement of the array element type. The type-name cannot be function type or an incomplete type.
The result is an integer constant of type size_t
.
The operand is not evaluated (so external identifiers used in the operand do not have to be defined).
Notes
The use of alignof with expressions (as in C++) is allowed by some C compilers as a non-standard extension.
Keywords
Example
#include <stdio.h> #include <stddef.h> #include <stdalign.h> int main(void) { printf("Alignment of char = %zu\n", alignof(char)); printf("Alignment of max_align_t = %zu\n", alignof(max_align_t)); printf("alignof(float[10]) = %zu\n", alignof(float[10])); printf("alignof(struct{char c; int n;}) = %zu\n", alignof(struct {char c; int n;})); }
Possible output:
Alignment of char = 1 Alignment of max_align_t = 16 alignof(float[10]) = 4 alignof(struct{char c; int n;}) = 4
References
- C11 standard (ISO/IEC 9899:2011):
- 6.5.3.4 The sizeof and _Alignof operators (p: 90-91)
See also
(C11) | a type with alignment requirement as great as any other scalar type (typedef) |
_Alignas specifier | sets alignment requirements of an object (since C11) |
C++ documentation for alignof operator |
Please login to continue.