std::mem_fun

Defined in header <functional>
template< class Res, class T > 
std::mem_fun_t<Res,T> mem_fun( Res (T::*f)() );
(1) (until C++17)
(deprecated since C++11)
template< class Res, class T > 
std::const_mem_fun_t<Res,T> mem_fun( Res (T::*f)() );
(1) (until C++17)
(deprecated since C++11)
template< class Res, class T, class Arg > 
std::mem_fun1_t<Res,T,Arg> mem_fun( Res (T::*f)(Arg) );
(2) (until C++17)
(deprecated since C++11)
template< class Res, class T, class Arg > 
std::const_mem_fun1_t<Res,T,Arg> mem_fun( S (T::*f)(Arg) );
(2) (until C++17)
(deprecated since C++11)

Creates a member function wrapper object, deducing the target type from the template arguments. The wrapper object expects a pointer to an object of type T as the first parameter to its operator().

1) Effectively calls std::mem_fun_t<S,T>(f) or std::const_mem_fun_t<S,T>(f).
2) Effectively calls std::mem_fun1_t<S,T>(f) or std::const_mem_fun1_t<S,T>(f).

This function and the related types were deprecated in C++11 and removed in C++17 in favor of the more general std::mem_fn and std::bind, both of which create callable adapter-compatible function objects from member functions.

Parameters

f - pointer to a member function to create a wrapper for

Return value

A function object wrapping f.

Exceptions

(none).

Notes

The difference between std::mem_fun and std::mem_fun_ref is that the former produces an function wrapper that expects a pointer to an object, whereas the latter -- a reference.

Example

See also

(until C++17)
creates a wrapper from a pointer to member function, callable with a reference to object
(function template)
doc_CPP
2016-10-11 10:04:46
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