Defined in header <algorithm> | ||
---|---|---|
(1) | ||
template< class ForwardIt > std::pair<ForwardIt,ForwardIt> minmax_element( ForwardIt first, ForwardIt last ); | (since C++11) (until C++17) | |
template< class ForwardIt > constexpr std::pair<ForwardIt,ForwardIt> minmax_element( ForwardIt first, ForwardIt last ); | (since C++17) | |
(2) | ||
template< class ForwardIt, class Compare > std::pair<ForwardIt,ForwardIt> minmax_element( ForwardIt first, ForwardIt last, Compare comp ); | (since C++11) (until C++17) | |
template< class ForwardIt, class Compare > constexpr std::pair<ForwardIt,ForwardIt> minmax_element( ForwardIt first, ForwardIt last, Compare comp ); | (since C++17) |
Finds the greatest and the smallest element in the range [first, last)
. The first version uses operator<
to compare the values, the second version uses the given comparison function comp
.
Parameters
first, last | - | forward iterators defining the range to examine |
cmp | - | comparison function object (i.e. an object that satisfies the requirements of Compare ) which returns true if if *a is less than *b . The signature of the comparison function should be equivalent to the following:
The signature does not need to have |
Type requirements | ||
- ForwardIt must meet the requirements of ForwardIterator . |
Return value
a pair consisting of an iterator to the smallest element as the first element and an iterator to the greatest element as the second. Returns std::make_pair(first, first)
if the range is empty. If several elements are equivalent to the smallest element, the iterator to the first such element is returned. If several elements are equivalent to the largest element, the iterator to the last such element is returned.
Complexity
At most max(floor(3/2(N−1)), 0) applications of the predicate, where N = std::distance(first, last)
.
Notes
This algorithm is different from std::make_pair(std::min_element(), std::max_element())
, not only in efficiency, but also in that this algorithm finds the last biggest element while std::max_element
finds the first biggest element.
Possible implementation
First version |
---|
template<class ForwardIt> std::pair<ForwardIt, ForwardIt> minmax_element(ForwardIt first, ForwardIt last) { return std::minmax_element(first, last, std::less<>()); } |
Second version |
template<class ForwardIt, class Compare> std::pair<ForwardIt, ForwardIt> minmax_element(ForwardIt first, ForwardIt last, Compare comp) { std::pair<ForwardIt, ForwardIt> result(first, first); if (first == last) return result; if (++first == last) return result; if (comp(*first, *result.first)) { result.first = first; } else { result.second = first; } while (++first != last) { ForwardIt i = first; if (++first == last) { if (comp(*i, *result.first)) result.first = i; else if (!(comp(*i, *result.second))) result.second = i; break; } else { if (comp(*first, *i)) { if (comp(*first, *result.first)) result.first = first; if (!(comp(*i, *result.second))) result.second = i; } else { if (comp(*i, *result.first)) result.first = i; if (!(comp(*first, *result.second))) result.second = first; } } } return result; } |
Example
#include <algorithm> #include <iostream> #include <vector> int main() { std::vector<int> v = { 3, 9, 1, 4, 2, 5, 9 }; auto result = std::minmax_element(v.begin(), v.end()); std::cout << "min element at: " << (result.first - v.begin()) << '\n'; std::cout << "max element at: " << (result.second - v.begin()) << '\n'; }
Output:
min element at: 2 max element at: 6
See also
returns the smallest element in a range (function template) | |
returns the largest element in a range (function template) | |
std::experimental::parallel::minmax_element
(parallelism TS) | parallelized version of std::minmax_element (function template) |
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