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DataFrame.sort(columns=None, axis=0, ascending=True, inplace=False, kind='quicksort', na_position='last', **kwargs)
[source] -
DEPRECATED: use
DataFrame.sort_values()
Sort DataFrame either by labels (along either axis) or by the values in column(s)
Parameters: columns : object
Column name(s) in frame. Accepts a column name or a list for a nested sort. A tuple will be interpreted as the levels of a multi-index.
ascending : boolean or list, default True
Sort ascending vs. descending. Specify list for multiple sort orders
axis : {0 or ?index?, 1 or ?columns?}, default 0
Sort index/rows versus columns
inplace : boolean, default False
Sort the DataFrame without creating a new instance
kind : {?quicksort?, ?mergesort?, ?heapsort?}, optional
This option is only applied when sorting on a single column or label.
na_position : {?first?, ?last?} (optional, default=?last?)
?first? puts NaNs at the beginning ?last? puts NaNs at the end
Returns: sorted : DataFrame
Examples
>>> result = df.sort(['A', 'B'], ascending=[1, 0])
DataFrame.sort()
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2025-01-10 15:47:30
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