-
numpy.isfortran(a)
[source] -
Returns True if the array is Fortran contiguous but not C contiguous.
This function is obsolete and, because of changes due to relaxed stride checking, its return value for the same array may differ for versions of Numpy >= 1.10 and previous versions. If you only want to check if an array is Fortran contiguous use
a.flags.f_contiguous
instead.Parameters: a : ndarray
Input array.
Examples
np.array allows to specify whether the array is written in C-contiguous order (last index varies the fastest), or FORTRAN-contiguous order in memory (first index varies the fastest).
123456>>> a
=
np.array([[
1
,
2
,
3
], [
4
,
5
,
6
]], order
=
'C'
)
>>> a
array([[
1
,
2
,
3
],
[
4
,
5
,
6
]])
>>> np.isfortran(a)
False
123456>>> b
=
np.array([[
1
,
2
,
3
], [
4
,
5
,
6
]], order
=
'FORTRAN'
)
>>> b
array([[
1
,
2
,
3
],
[
4
,
5
,
6
]])
>>> np.isfortran(b)
True
The transpose of a C-ordered array is a FORTRAN-ordered array.
12345678910111213>>> a
=
np.array([[
1
,
2
,
3
], [
4
,
5
,
6
]], order
=
'C'
)
>>> a
array([[
1
,
2
,
3
],
[
4
,
5
,
6
]])
>>> np.isfortran(a)
False
>>> b
=
a.T
>>> b
array([[
1
,
4
],
[
2
,
5
],
[
3
,
6
]])
>>> np.isfortran(b)
True
C-ordered arrays evaluate as False even if they are also FORTRAN-ordered.
12>>> np.isfortran(np.array([
1
,
2
], order
=
'FORTRAN'
))
False
numpy.isfortran()

2025-01-10 15:47:30
Please login to continue.