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numpy.polynomial.hermite_e.hermeval(x, c, tensor=True)
[source] -
Evaluate an HermiteE series at points x.
If
c
is of lengthn + 1
, this function returns the value:The parameter
x
is converted to an array only if it is a tuple or a list, otherwise it is treated as a scalar. In either case, eitherx
or its elements must support multiplication and addition both with themselves and with the elements ofc
.If
c
is a 1-D array, thenp(x)
will have the same shape asx
. Ifc
is multidimensional, then the shape of the result depends on the value oftensor
. Iftensor
is true the shape will be c.shape[1:] + x.shape. Iftensor
is false the shape will be c.shape[1:]. Note that scalars have shape (,).Trailing zeros in the coefficients will be used in the evaluation, so they should be avoided if efficiency is a concern.
Parameters: x : array_like, compatible object
If
x
is a list or tuple, it is converted to an ndarray, otherwise it is left unchanged and treated as a scalar. In either case,x
or its elements must support addition and multiplication with with themselves and with the elements ofc
.c : array_like
Array of coefficients ordered so that the coefficients for terms of degree n are contained in c[n]. If
c
is multidimensional the remaining indices enumerate multiple polynomials. In the two dimensional case the coefficients may be thought of as stored in the columns ofc
.tensor : boolean, optional
If True, the shape of the coefficient array is extended with ones on the right, one for each dimension of
x
. Scalars have dimension 0 for this action. The result is that every column of coefficients inc
is evaluated for every element ofx
. If False,x
is broadcast over the columns ofc
for the evaluation. This keyword is useful whenc
is multidimensional. The default value is True.New in version 1.7.0.
Returns: values : ndarray, algebra_like
The shape of the return value is described above.
See also
Notes
The evaluation uses Clenshaw recursion, aka synthetic division.
Examples
>>> from numpy.polynomial.hermite_e import hermeval >>> coef = [1,2,3] >>> hermeval(1, coef) 3.0 >>> hermeval([[1,2],[3,4]], coef) array([[ 3., 14.], [ 31., 54.]])
numpy.polynomial.hermite_e.hermeval()
2017-01-10 18:17:09
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