numpy.polynomial.legendre.legsub()

numpy.polynomial.legendre.legsub(c1, c2) [source]

Subtract one Legendre series from another.

Returns the difference of two Legendre series c1 - c2. The sequences of coefficients are from lowest order term to highest, i.e., [1,2,3] represents the series P_0 + 2*P_1 + 3*P_2.

Parameters:

Parameters:	c1, c2 : array_like 1-D arrays of Legendre series coefficients ordered from low to high.
Returns:	out : ndarray Of Legendre series coefficients representing their difference.

c1, c2 : array_like

1-D arrays of Legendre series coefficients ordered from low to high.

Returns:

out : ndarray

Of Legendre series coefficients representing their difference.

Notes

Unlike multiplication, division, etc., the difference of two Legendre series is a Legendre series (without having to ?reproject? the result onto the basis set) so subtraction, just like that of ?standard? polynomials, is simply ?component-wise.?

Examples

>>> from numpy.polynomial import legendre as L
>>> c1 = (1,2,3)
>>> c2 = (3,2,1)
>>> L.legsub(c1,c2)
array([-2.,  0.,  2.])
>>> L.legsub(c2,c1) # -C.legsub(c1,c2)
array([ 2.,  0., -2.])

Links:

https://docs.scipy.org/doc/numpy-1.11.0/reference/generated/numpy.polynomial.legendre.legsub.html

doc_NumPy

2025-01-10 15:47:30

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