pandas.to_timedelta()

pandas.to_timedelta(*args, **kwargs) [source]

Convert argument to timedelta

Parameters:

Parameters:	arg : string, timedelta, list, tuple, 1-d array, or Series unit : unit of the arg (D,h,m,s,ms,us,ns) denote the unit, which is an integer/float number box : boolean, default True If True returns a Timedelta/TimedeltaIndex of the results if False returns a np.timedelta64 or ndarray of values of dtype timedelta64[ns] errors : {?ignore?, ?raise?, ?coerce?}, default ?raise? If ?raise?, then invalid parsing will raise an exception If ?coerce?, then invalid parsing will be set as NaT If ?ignore?, then invalid parsing will return the input
Returns:	ret : timedelta64/arrays of timedelta64 if parsing succeeded

arg : string, timedelta, list, tuple, 1-d array, or Series

unit : unit of the arg (D,h,m,s,ms,us,ns) denote the unit, which is an

integer/float number

box : boolean, default True

If True returns a Timedelta/TimedeltaIndex of the results
if False returns a np.timedelta64 or ndarray of values of dtype timedelta64[ns]

errors : {?ignore?, ?raise?, ?coerce?}, default ?raise?

If ?raise?, then invalid parsing will raise an exception
If ?coerce?, then invalid parsing will be set as NaT
If ?ignore?, then invalid parsing will return the input

Returns:

ret : timedelta64/arrays of timedelta64 if parsing succeeded

Examples

Parsing a single string to a Timedelta:

>>> pd.to_timedelta('1 days 06:05:01.00003')
Timedelta('1 days 06:05:01.000030')
>>> pd.to_timedelta('15.5us')
Timedelta('0 days 00:00:00.000015')

Parsing a list or array of strings:

>>> pd.to_timedelta(['1 days 06:05:01.00003', '15.5us', 'nan'])
TimedeltaIndex(['1 days 06:05:01.000030', '0 days 00:00:00.000015', NaT],
               dtype='timedelta64[ns]', freq=None)

Converting numbers by specifying the unit keyword argument:

>>> pd.to_timedelta(np.arange(5), unit='s')
TimedeltaIndex(['00:00:00', '00:00:01', '00:00:02',
                '00:00:03', '00:00:04'],
               dtype='timedelta64[ns]', freq=None)
>>> pd.to_timedelta(np.arange(5), unit='d')
TimedeltaIndex(['0 days', '1 days', '2 days', '3 days', '4 days'],
               dtype='timedelta64[ns]', freq=None)

Links:

http://pandas.pydata.org/pandas-docs/version/0.19.2/generated/pandas.to_timedelta.html

doc_Pandas

2017-01-12 04:50:40

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