if-else
statements don't work inside JSX. This is because JSX is just syntactic sugar for function calls and object construction. Take this basic example:
1 2 3 4 5 | // This JSX: ReactDOM.render(<div id= "msg" >Hello World!</div>, mountNode); // Is transformed to this JS: ReactDOM.render(React.createElement( "div" , {id: "msg" }, "Hello World!" ), mountNode); |
This means that if
statements don't fit in. Take this example:
1 2 3 4 5 | // This JSX: <div id={ if (condition) { 'msg' }}>Hello World!</div> // Is transformed to this JS: React.createElement( "div" , {id: if (condition) { 'msg' }}, "Hello World!" ); |
That's not valid JS. You probably want to make use of a ternary expression:
1 | ReactDOM.render(<div id={condition ? 'msg' : null }>Hello World!</div>, mountNode); |
If a ternary expression isn't robust enough, you can use if
statements outside of your JSX to determine which components should be used:
1 2 3 4 5 6 7 8 9 10 11 12 13 | var loginButton; if (loggedIn) { loginButton = <LogoutButton />; } else { loginButton = <LoginButton />; } return ( <nav> <Home /> {loginButton} </nav> ); |
Or if you prefer a more "inline" aesthetic, define immediately-invoked function expressions inside your JSX:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 | return ( <section> <h1>Color</h1> <h3>Name</h3> <p>{ this .state.color || "white" }</p> <h3>Hex</h3> <p> {(() => { switch ( this .state.color) { case "red" : return "#FF0000" ; case "green" : return "#00FF00" ; case "blue" : return "#0000FF" ; default : return "#FFFFFF" ; } })()} </p> </section> ); |
In the example above, an ES6 arrow function is utilized to lexically bind the value of
this
.
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