most_common([n])
Return a list of the n most common elements and their counts from the most common to the least. If n is omitted or None
, most_common()
returns all elements in the counter. Elements with equal counts are ordered arbitrarily:
1 2 | >>> Counter( 'abracadabra' ).most_common(3) [( 'a' , 5), ( 'r' , 2), ( 'b' , 2)] |
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