match.end([group])
Return the indices of the start and end of the substring matched by group; group defaults to zero (meaning the whole matched substring). Return -1
if group exists but did not contribute to the match. For a match object m, and a group g that did contribute to the match, the substring matched by group g (equivalent to m.group(g)
) is
m.string[m.start(g):m.end(g)]
Note that m.start(group)
will equal m.end(group)
if group matched a null string. For example, after m = re.search('b(c?)', 'cba')
, m.start(0)
is 1, m.end(0)
is 2, m.start(1)
and m.end(1)
are both 2, and m.start(2)
raises an IndexError
exception.
An example that will remove remove_this from email addresses:
>>> email = "tony@tiremove_thisger.net" >>> m = re.search("remove_this", email) >>> email[:m.start()] + email[m.end():] 'tony@tiger.net'
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