Defined in header <algorithm> | ||
---|---|---|
template< class BidirIt > bool prev_permutation( BidirIt first, BidirIt last); | (1) | |
template< class BidirIt, class Compare > bool prev_permutation( BidirIt first, BidirIt last, Compare comp); | (2) |
Transforms the range [first, last)
into the previous permutation from the set of all permutations that are lexicographically ordered with respect to operator<
or comp
. Returns true
if such permutation exists, otherwise transforms the range into the last permutation (as if by std::sort(first, last); std::reverse(first, last);
) and returns false
.
Parameters
first, last | - | the range of elements to permute |
comp | - | comparison function object (i.e. an object that satisfies the requirements of Compare ) which returns true if the first argument is less than the second. The signature of the comparison function should be equivalent to the following:
The signature does not need to have |
Type requirements | ||
- BidirIt must meet the requirements of ValueSwappable and BidirectionalIterator . |
Return value
true
if the new permutation precedes the old in lexicographical order. false
if the first permutation was reached and the range was reset to the last permutation.
Exceptions
Any exceptions thrown from iterator operations or the element swap.
Complexity
At most (last-first)/2
swaps.
Possible implementation
template<class BidirIt> bool prev_permutation(BidirIt first, BidirIt last) { if (first == last) return false; BidirIt i = last; if (first == --i) return false; while (1) { BidirIt i1, i2; i1 = i; if (*i1 < *--i) { i2 = last; while (!(*--i2 < *i)) ; std::iter_swap(i, i2); std::reverse(i1, last); return true; } if (i == first) { std::reverse(first, last); return false; } } } |
Example
The following code prints all six permutations of the string "abc" in reverse order.
#include <algorithm> #include <string> #include <iostream> #include <functional> int main() { std::string s="abc"; std::sort(s.begin(), s.end(), std::greater<char>()); do { std::cout << s << ' '; } while(std::prev_permutation(s.begin(), s.end())); std::cout << '\n'; }
Output:
cba cab bca bac acb abc
See also
(C++11) | determines if a sequence is a permutation of another sequence (function template) |
generates the next greater lexicographic permutation of a range of elements (function template) |
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