| Defined in header <algorithm> | ||
|---|---|---|
template< class ForwardIt, class OutputIt >
OutputIt rotate_copy( ForwardIt first, ForwardIt n_first,
ForwardIt last, OutputIt d_first ); |
Copies the elements from the range [first, last), to another range beginning at d_first in such a way, that the element n_first becomes the first element of the new range and n_first - 1 becomes the last element.
Parameters
| first, last | - | the range of elements to copy |
| n_first | - | an iterator to an element in [first, last) that should appear at the beginning of the new range |
| d_first | - | beginning of the destination range |
| Type requirements | ||
- ForwardIt must meet the requirements of ForwardIterator. | ||
- OutputIt must meet the requirements of OutputIterator. | ||
Return value
Output iterator to the element past the last element copied.
Possible implementation
template<class ForwardIt, class OutputIt>
OutputIt rotate_copy(ForwardIt first, ForwardIt n_first,
ForwardIt last, OutputIt d_first)
{
d_first = std::copy(n_first, last, d_first);
return std::copy(first, n_first, d_first);
} |
Example
#include <algorithm>
#include <vector>
#include <iostream>
int main()
{
std::vector<int> src = {1, 2, 3, 4, 5};
auto pivot = std::find(src.begin(), src.end(), 3);
std::vector<int> dest(src.size());
std::rotate_copy(src.begin(), pivot, src.end(), dest.begin());
for (const auto &i : dest) {
std::cout << i << ' ';
}
std::cout << '\n';
}Output:
3 4 5 1 2
Complexity
linear in the distance between first and last.
See also
| rotates the order of elements in a range (function template) | |
| std::experimental::parallel::rotate_copy
(parallelism TS) | parallelized version of std::rotate_copy (function template) |
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