|   Defined in header   <algorithm>  |  ||
|---|---|---|
 template< class ForwardIt, class OutputIt >
OutputIt rotate_copy( ForwardIt first, ForwardIt n_first,
                      ForwardIt last, OutputIt d_first );  |  
Copies the elements from the range [first, last), to another range beginning at d_first in such a way, that the element n_first becomes the first element of the new range and n_first - 1 becomes the last element.
Parameters
| first, last | - | the range of elements to copy | 
| n_first | - |  an iterator to an element in [first, last) that should appear at the beginning of the new range  |  
| d_first | - | beginning of the destination range | 
| Type requirements | ||
 - ForwardIt must meet the requirements of ForwardIterator.  |  ||
 - OutputIt must meet the requirements of OutputIterator.  |  ||
Return value
Output iterator to the element past the last element copied.
Possible implementation
 template<class ForwardIt, class OutputIt>
OutputIt rotate_copy(ForwardIt first, ForwardIt n_first,
                           ForwardIt last, OutputIt d_first)
{
    d_first = std::copy(n_first, last, d_first);
    return std::copy(first, n_first, d_first);
} |  
Example
#include <algorithm>
#include <vector>
#include <iostream>
 
int main()
{
    std::vector<int> src = {1, 2, 3, 4, 5}; 
    auto pivot = std::find(src.begin(), src.end(), 3); 
    std::vector<int> dest(src.size());                                          
 
    std::rotate_copy(src.begin(), pivot, src.end(), dest.begin());
 
    for (const auto &i : dest) {
        std::cout << i << ' ';
    }   
    std::cout << '\n';
}Output:
3 4 5 1 2
Complexity
linear in the distance between first and last.
See also
|  rotates the order of elements in a range  (function template)  |  |
|    std::experimental::parallel::rotate_copy
  (parallelism TS)   |   parallelized version of std::rotate_copy (function template)  |  
Please login to continue.