Defined in header <algorithm> | ||
---|---|---|
template< class ForwardIt, class OutputIt > OutputIt rotate_copy( ForwardIt first, ForwardIt n_first, ForwardIt last, OutputIt d_first ); |
Copies the elements from the range [first, last)
, to another range beginning at d_first
in such a way, that the element n_first
becomes the first element of the new range and n_first - 1
becomes the last element.
Parameters
first, last | - | the range of elements to copy |
n_first | - | an iterator to an element in [first, last) that should appear at the beginning of the new range |
d_first | - | beginning of the destination range |
Type requirements | ||
- ForwardIt must meet the requirements of ForwardIterator . | ||
- OutputIt must meet the requirements of OutputIterator . |
Return value
Output iterator to the element past the last element copied.
Possible implementation
template<class ForwardIt, class OutputIt> OutputIt rotate_copy(ForwardIt first, ForwardIt n_first, ForwardIt last, OutputIt d_first) { d_first = std::copy(n_first, last, d_first); return std::copy(first, n_first, d_first); } |
Example
#include <algorithm> #include <vector> #include <iostream> int main() { std::vector<int> src = {1, 2, 3, 4, 5}; auto pivot = std::find(src.begin(), src.end(), 3); std::vector<int> dest(src.size()); std::rotate_copy(src.begin(), pivot, src.end(), dest.begin()); for (const auto &i : dest) { std::cout << i << ' '; } std::cout << '\n'; }
Output:
3 4 5 1 2
Complexity
linear in the distance between first
and last
.
See also
rotates the order of elements in a range (function template) | |
std::experimental::parallel::rotate_copy
(parallelism TS) | parallelized version of std::rotate_copy (function template) |
Please login to continue.