-
numpy.bitwise_or(x1, x2[, out]) =
-
Compute the bit-wise OR of two arrays element-wise.
Computes the bit-wise OR of the underlying binary representation of the integers in the input arrays. This ufunc implements the C/Python operator
|
.Parameters: x1, x2 : array_like
Only integer and boolean types are handled.
out : ndarray, optional
Array into which the output is placed. Its type is preserved and it must be of the right shape to hold the output. See doc.ufuncs.
Returns: out : array_like
Result.
See also
logical_or
,bitwise_and
,bitwise_xor
-
binary_repr
- Return the binary representation of the input number as a string.
Examples
The number 13 has the binaray representation
00001101
. Likewise, 16 is represented by00010000
. The bit-wise OR of 13 and 16 is then000111011
, or 29:1234>>> np.bitwise_or(
13
,
16
)
29
>>> np.binary_repr(
29
)
'11101'
123456>>> np.bitwise_or(
32
,
2
)
34
>>> np.bitwise_or([
33
,
4
],
1
)
array([
33
,
5
])
>>> np.bitwise_or([
33
,
4
], [
1
,
2
])
array([
33
,
6
])
123456789>>> np.bitwise_or(np.array([
2
,
5
,
255
]), np.array([
4
,
4
,
4
]))
array([
6
,
5
,
255
])
>>> np.array([
2
,
5
,
255
]) | np.array([
4
,
4
,
4
])
array([
6
,
5
,
255
])
>>> np.bitwise_or(np.array([
2
,
5
,
255
,
2147483647L
], dtype
=
np.int32),
... np.array([
4
,
4
,
4
,
2147483647L
], dtype
=
np.int32))
array([
6
,
5
,
255
,
2147483647
])
>>> np.bitwise_or([
True
,
True
], [
False
,
True
])
array([
True
,
True
], dtype
=
bool
)
-
numpy.bitwise_or()

2025-01-10 15:47:30
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