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numpy.core.defchararray.count(a, sub, start=0, end=None)
[source] -
Returns an array with the number of non-overlapping occurrences of substring
sub
in the range [start
,end
].Calls
str.count
element-wise.Parameters: a : array_like of str or unicode
sub : str or unicode
The substring to search for.
start, end : int, optional
Optional arguments
start
andend
are interpreted as slice notation to specify the range in which to count.Returns: out : ndarray
Output array of ints.
See also
Examples
>>> c = np.array(['aAaAaA', ' aA ', 'abBABba']) >>> c array(['aAaAaA', ' aA ', 'abBABba'], dtype='|S7') >>> np.char.count(c, 'A') array([3, 1, 1]) >>> np.char.count(c, 'aA') array([3, 1, 0]) >>> np.char.count(c, 'A', start=1, end=4) array([2, 1, 1]) >>> np.char.count(c, 'A', start=1, end=3) array([1, 0, 0])
numpy.core.defchararray.count()
2017-01-10 18:13:13
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