numpy.setdiff1d()

numpy.setdiff1d(ar1, ar2, assume_unique=False) [source]

Find the set difference of two arrays.

Return the sorted, unique values in ar1 that are not in ar2.

Parameters:

Parameters:	ar1 : array_like Input array. ar2 : array_like Input comparison array. assume_unique : bool If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False.
Returns:	setdiff1d : ndarray Sorted 1D array of values in `ar1` that are not in `ar2`.

ar1 : array_like

Input array.

ar2 : array_like

Input comparison array.

assume_unique : bool

If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False.

Returns:

setdiff1d : ndarray

Sorted 1D array of values in ar1 that are not in ar2.

>>> a = np.array([1, 2, 3, 2, 4, 1])
>>> b = np.array([3, 4, 5, 6])
>>> np.setdiff1d(a, b)
array([1, 2])

Links:

doc_NumPy

2025-01-10 15:47:30

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