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GroupBy.tail(n=5)
[source] -
Returns last n rows of each group
Essentially equivalent to
.apply(lambda x: x.tail(n))
, except ignores as_index flag.Examples
>>> df = DataFrame([['a', 1], ['a', 2], ['b', 1], ['b', 2]], columns=['A', 'B']) >>> df.groupby('A').tail(1) A B 1 a 2 3 b 2 >>> df.groupby('A').head(1) A B 0 a 1 2 b 1
GroupBy.tail()
2017-01-12 04:48:31
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