SeriesGroupBy.nlargest()

SeriesGroupBy.nlargest(*args, **kwargs) [source]

Return the largest n elements.

Parameters:

Parameters:	n : int Return this many descending sorted values keep : {?first?, ?last?, False}, default ?first? Where there are duplicate values: - `first` : take the first occurrence. - `last` : take the last occurrence. take_last : deprecated
Returns:	top_n : Series The n largest values in the Series, in sorted order

n : int

Return this many descending sorted values

keep : {?first?, ?last?, False}, default ?first?

Where there are duplicate values: - first : take the first occurrence. - last : take the last occurrence.

take_last : deprecated

Returns:

top_n : Series

The n largest values in the Series, in sorted order

Faster than .sort_values(ascending=False).head(n) for small n relative to the size of the Series object.

>>> import pandas as pd
>>> import numpy as np
>>> s = pd.Series(np.random.randn(1e6))
>>> s.nlargest(10)  # only sorts up to the N requested

Links:

doc_Pandas

2017-01-12 04:55:22

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