numpy.ma.is_masked()

numpy.ma.is_masked(x) [source]

Determine whether input has masked values.

Accepts any object as input, but always returns False unless the input is a MaskedArray containing masked values.

Parameters:

Parameters:	x : array_like Array to check for masked values.
Returns:	result : bool True if `x` is a MaskedArray with masked values, False otherwise.

x : array_like

Array to check for masked values.

Returns:

result : bool

True if x is a MaskedArray with masked values, False otherwise.

Examples

>>> import numpy.ma as ma
>>> x = ma.masked_equal([0, 1, 0, 2, 3], 0)
>>> x
masked_array(data = [-- 1 -- 2 3],
      mask = [ True False  True False False],
      fill_value=999999)
>>> ma.is_masked(x)
True
>>> x = ma.masked_equal([0, 1, 0, 2, 3], 42)
>>> x
masked_array(data = [0 1 0 2 3],
      mask = False,
      fill_value=999999)
>>> ma.is_masked(x)
False

Always returns False if x isn?t a MaskedArray.

>>> x = [False, True, False]
>>> ma.is_masked(x)
False
>>> x = 'a string'
>>> ma.is_masked(x)
False

Links:

https://docs.scipy.org/doc/numpy-1.11.0/reference/generated/numpy.ma.is_masked.html

doc_NumPy

2025-01-10 15:47:30

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