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numpy.diff(a, n=1, axis=-1)
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Calculate the n-th discrete difference along given axis.
The first difference is given by
out[n] = a[n+1] - a[n]
along the given axis, higher differences are calculated by usingdiff
recursively.Parameters: a : array_like
Input array
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n : int, optional
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The number of times values are differenced.
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axis : int, optional
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The axis along which the difference is taken, default is the last axis.
Returns: diff : ndarray
The n-th differences. The shape of the output is the same as
a
except alongaxis
where the dimension is smaller byn
..
Examples
>>> x = np.array([1, 2, 4, 7, 0]) >>> np.diff(x) array([ 1, 2, 3, -7]) >>> np.diff(x, n=2) array([ 1, 1, -10])
>>> x = np.array([[1, 3, 6, 10], [0, 5, 6, 8]]) >>> np.diff(x) array([[2, 3, 4], [5, 1, 2]]) >>> np.diff(x, axis=0) array([[-1, 2, 0, -2]])
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numpy.diff()
2017-01-10 18:13:41
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