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numpy.floor_divide(x1, x2[, out]) = -
Return the largest integer smaller or equal to the division of the inputs. It is equivalent to the Python
//operator and pairs with the Python%(remainder), function so thatb = a % b + b * (a // b)up to roundoff.Parameters: x1 : array_like
Numerator.
x2 : array_like
Denominator.
Returns: y : ndarray
y = floor(
x1/x2)See also
Examples
1234>>> np.floor_divide(7,3)2>>> np.floor_divide([1.,2.,3.,4.],2.5)array([0.,0.,1.,1.])
numpy.floor_divide()
2025-01-10 15:47:30
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