numpy.core.defchararray.count()

numpy.core.defchararray.count(a, sub, start=0, end=None) [source]

Returns an array with the number of non-overlapping occurrences of substring sub in the range [start, end].

Calls str.count element-wise.

Parameters:

Parameters:	a : array_like of str or unicode sub : str or unicode The substring to search for. start, end : int, optional Optional arguments `start` and `end` are interpreted as slice notation to specify the range in which to count.
Returns:	out : ndarray Output array of ints.

a : array_like of str or unicode

sub : str or unicode

The substring to search for.

start, end : int, optional

Optional arguments start and end are interpreted as slice notation to specify the range in which to count.

Returns:

out : ndarray

Output array of ints.

Examples

>>> c = np.array(['aAaAaA', '  aA  ', 'abBABba'])
>>> c
array(['aAaAaA', '  aA  ', 'abBABba'],
    dtype='|S7')
>>> np.char.count(c, 'A')
array([3, 1, 1])
>>> np.char.count(c, 'aA')
array([3, 1, 0])
>>> np.char.count(c, 'A', start=1, end=4)
array([2, 1, 1])
>>> np.char.count(c, 'A', start=1, end=3)
array([1, 0, 0])

Links:

https://docs.scipy.org/doc/numpy-1.11.0/reference/generated/numpy.core.defchararray.count.html

doc_NumPy

2017-01-10 18:13:13

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