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numpy.fft.ifft(a, n=None, axis=-1, norm=None)
[source] -
Compute the one-dimensional inverse discrete Fourier Transform.
This function computes the inverse of the one-dimensional n-point discrete Fourier transform computed by
fft
. In other words,ifft(fft(a)) == a
to within numerical accuracy. For a general description of the algorithm and definitions, seenumpy.fft
.The input should be ordered in the same way as is returned by
fft
, i.e.,-
a[0]
should contain the zero frequency term, -
a[1:n//2]
should contain the positive-frequency terms, -
a[n//2 + 1:]
should contain the negative-frequency terms, in increasing order starting from the most negative frequency.
For an even number of input points,
A[n//2]
represents the sum of the values at the positive and negative Nyquist frequencies, as the two are aliased together. Seenumpy.fft
for details.Parameters: a : array_like
Input array, can be complex.
n : int, optional
Length of the transformed axis of the output. If
n
is smaller than the length of the input, the input is cropped. If it is larger, the input is padded with zeros. Ifn
is not given, the length of the input along the axis specified byaxis
is used. See notes about padding issues.axis : int, optional
Axis over which to compute the inverse DFT. If not given, the last axis is used.
norm : {None, ?ortho?}, optional
New in version 1.10.0.
Normalization mode (see
numpy.fft
). Default is None.Returns: out : complex ndarray
The truncated or zero-padded input, transformed along the axis indicated by
axis
, or the last one ifaxis
is not specified.Raises: IndexError
If
axes
is larger than the last axis ofa
.See also
Notes
If the input parameter
n
is larger than the size of the input, the input is padded by appending zeros at the end. Even though this is the common approach, it might lead to surprising results. If a different padding is desired, it must be performed before callingifft
.Examples
>>> np.fft.ifft([0, 4, 0, 0]) array([ 1.+0.j, 0.+1.j, -1.+0.j, 0.-1.j])
Create and plot a band-limited signal with random phases:
>>> import matplotlib.pyplot as plt >>> t = np.arange(400) >>> n = np.zeros((400,), dtype=complex) >>> n[40:60] = np.exp(1j*np.random.uniform(0, 2*np.pi, (20,))) >>> s = np.fft.ifft(n) >>> plt.plot(t, s.real, 'b-', t, s.imag, 'r--') ... >>> plt.legend(('real', 'imaginary')) ... >>> plt.show()
(Source code, png, pdf)
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numpy.fft.ifft()
2017-01-10 18:13:54
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