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numpy.ma.resize(x, new_shape)
[source] -
Return a new masked array with the specified size and shape.
This is the masked equivalent of the
numpy.resize
function. The new array is filled with repeated copies ofx
(in the order that the data are stored in memory). Ifx
is masked, the new array will be masked, and the new mask will be a repetition of the old one.See also
-
numpy.resize
- Equivalent function in the top level NumPy module.
Examples
>>> import numpy.ma as ma >>> a = ma.array([[1, 2] ,[3, 4]]) >>> a[0, 1] = ma.masked >>> a masked_array(data = [[1 --] [3 4]], mask = [[False True] [False False]], fill_value = 999999) >>> np.resize(a, (3, 3)) array([[1, 2, 3], [4, 1, 2], [3, 4, 1]]) >>> ma.resize(a, (3, 3)) masked_array(data = [[1 -- 3] [4 1 --] [3 4 1]], mask = [[False True False] [False False True] [False False False]], fill_value = 999999)
A MaskedArray is always returned, regardless of the input type.
>>> a = np.array([[1, 2] ,[3, 4]]) >>> ma.resize(a, (3, 3)) masked_array(data = [[1 2 3] [4 1 2] [3 4 1]], mask = False, fill_value = 999999)
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numpy.ma.resize()
2017-01-10 18:15:47
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