itertools.zip_longest(*iterables, fillvalue=None) Make an iterator that aggregates elements from each of the iterables. If the

operator.__mul__(a, b) Return a * b, for a and b numbers.

itertools.tee(iterable, n=2) Return n independent iterators from a single iterable. Roughly equivalent to:

operator.__itruediv__(a, b) a = itruediv(a, b) is equivalent to a /= b.

itertools.product(*iterables, repeat=1) Cartesian product of input iterables. Roughly equivalent

operator.eq(a, b) operator.ne(a, b) operator.ge(a, b) operator

operator.__iconcat__(a, b) a = iconcat(a, b) is equivalent to a += b for a and b

operator.concat(a, b) operator.__concat__(a, b) Return a + b for a and b sequences

operator.pow(a, b) operator.__pow__(a, b) Return a ** b, for a and b numbers.

operator.__or__(a, b) Return the bitwise or of a and b.