itertools.compress(data, selectors) Make an iterator that filters elements from data returning only those that have

operator.eq(a, b) operator.ne(a, b) operator.ge(a, b) operator

itertools.zip_longest(*iterables, fillvalue=None) Make an iterator that aggregates elements from each of the iterables. If the

itertools.product(*iterables, repeat=1) Cartesian product of input iterables. Roughly equivalent

operator.length_hint(obj, default=0) Return an estimated length for the object o. First try to return its actual length

operator.add(a, b) operator.__add__(a, b) Return a + b, for a and b numbers.

operator.__pos__(obj) Return obj positive (+obj).

operator.inv(obj) operator.invert(obj) operator.__inv__(obj) operator

operator.concat(a, b) operator.__concat__(a, b) Return a + b for a and b sequences

itertools.chain(*iterables) Make an iterator that returns elements from the first iterable until it is exhausted, then proceeds