operator.ixor()
  • References/Python/Python/Functional Programming

operator.ixor(a, b) operator.__ixor__(a, b) a = ixor(a, b) is equivalent to a ^= b.

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itertools.chain()
  • References/Python/Python/Functional Programming

itertools.chain(*iterables) Make an iterator that returns elements from the first iterable until it is exhausted, then proceeds

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operator.length_hint()
  • References/Python/Python/Functional Programming

operator.length_hint(obj, default=0) Return an estimated length for the object o. First try to return its actual length

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operator.
  • References/Python/Python/Functional Programming

operator.__pow__(a, b) Return a ** b, for a and b numbers.

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operator.inv()
  • References/Python/Python/Functional Programming

operator.inv(obj) operator.invert(obj) operator.__inv__(obj) operator

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operator.ipow()
  • References/Python/Python/Functional Programming

operator.ipow(a, b) operator.__ipow__(a, b) a = ipow(a, b) is equivalent to a **= b.

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operator.
  • References/Python/Python/Functional Programming

operator.__index__(a) Return a converted to an integer. Equivalent to a.__index__().

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itertools.permutations()
  • References/Python/Python/Functional Programming

itertools.permutations(iterable, r=None) Return successive r length permutations of elements in the iterable

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operator.
  • References/Python/Python/Functional Programming

operator.__eq__(a, b) operator.__ne__(a, b) operator.__ge__(a, b) operator

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itertools.zip_longest()
  • References/Python/Python/Functional Programming

itertools.zip_longest(*iterables, fillvalue=None) Make an iterator that aggregates elements from each of the iterables. If the

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